Calculus I · Limits and Continuity · practice

Continuity and IVT Practice Problems

Visual study stop

Read the picture before the symbols

Pause at each graph long enough to say what the input is doing, what the output is doing, and which feature supports the next mathematical decision.

Classify the shape before choosing a repair

A removable hole, jump, vertical blow-up, and oscillation fail continuity for different reasons. Only a removable mismatch can be repaired by changing one function value.

Continuous cubic crossing the x-axis between endpoints of opposite sign.
Read this graph as text

A root guaranteed by the Intermediate Value Theorem. The continuous curve f(x) = x cubed + x - 1 is shown on the closed interval from 0 to 1. A filled circle at (0, -1) lies below the x-axis and a filled square at (1, 1) lies above it. The curve crosses the axis at a filled diamond c approximately 0.6823, illustrating a root whose existence the Intermediate Value Theorem guarantees.

The negative endpoint is a filled circle, the positive endpoint is a filled square, and the root is a filled diamond, all with text labels.

Why it matters: Show how continuity and opposite endpoint signs guarantee at least one zero between the endpoints.

Use continuity to justify existence, not exactness

Opposite endpoint signs and continuity guarantee a root in the interval. They do not locate it exactly or prove that it is the only root.

Section 5 Exercises

A. Three-part continuity test

Exercise 1

Is f(x)=x2+1f(x)=x^2+1 continuous at x=2x=2? Verify all three conditions.

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Yes; value and limit both equal 55.

Answer 1 from the source-traced unit appendix.
Exercise 2

Is g(x)=1/(x3)g(x)=1/(x-3) continuous at x=3x=3? Identify the first failed condition.

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No; the function value is undefined and behavior is unbounded.

Answer 2 from the source-traced unit appendix.
Exercise 3

A function has f(1)=4f(1)=4 and limx1f(x)=4\lim_{x\to1}f(x)=4. Is it continuous at 11?

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Yes.

Answer 3 from the source-traced unit appendix.
Exercise 4

A function has f(1)=4f(1)=4 and limx1f(x)=5\lim_{x\to1}f(x)=5. Which condition fails?

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The equality condition fails.

Answer 4 from the source-traced unit appendix.
Exercise 5

A function is undefined at 22, but its limit there is 77. Which conditions fail?

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The function-value condition fails, and therefore the equality condition cannot hold.

Answer 5 from the source-traced unit appendix.
Exercise 6

A function has unequal one-sided limits at 00. Can it be continuous there?

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No.

Answer 6 from the source-traced unit appendix.
Exercise 7

Explain why existence of f(a)f(a) alone says nothing about continuity.

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A dot may be isolated from the nearby graph.

Answer 7 from the source-traced unit appendix.
Exercise 8

Explain why existence of a finite limit alone does not guarantee continuity.

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The value may be missing or different from the limit.

Answer 8 from the source-traced unit appendix.

B. Intervals of continuity

Exercise 9

Find intervals of continuity of 1/(x24)1/(x^2-4).

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(,2)(2,2)(2,)( -\infty,-2)\cup(-2,2)\cup(2,\infty).

Answer 9 from the source-traced unit appendix.
Exercise 10

Find intervals of continuity of x1\sqrt{x-1}.

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[1,)[1,\infty).

Answer 10 from the source-traced unit appendix.
Exercise 11

Find intervals of continuity of 5x/(x+2)\sqrt{5-x}/(x+2).

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(,2)(2,5]( -\infty,-2)\cup(-2,5].

Answer 11 from the source-traced unit appendix.
Exercise 12

Find intervals of continuity of ln(x+3)\ln(x+3).

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(3,)(-3,\infty).

Answer 12 from the source-traced unit appendix.
Exercise 13

Find intervals of continuity of tanx\tan x on [2π,2π][-2\pi,2\pi].

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Break at 3π/2,π/2,π/2,3π/2-3\pi/2,-\pi/2,\pi/2,3\pi/2; continuous on the resulting subintervals.

Answer 13 from the source-traced unit appendix.
Exercise 14

Find intervals of continuity of x+2/(x29)\sqrt{x+2}/(x^2-9).

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[2,3)(3,)[-2,3)\cup(3,\infty).

Answer 14 from the source-traced unit appendix.
Exercise 15

Find the domain and intervals of continuity of ln(9x2)\ln(9-x^2).

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(3,3)(-3,3).

Answer 15 from the source-traced unit appendix.
Exercise 16

Explain endpoint continuity for f(x)=4x2f(x)=\sqrt{4-x^2} on [2,2][-2,2].

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Continuous on [2,2][-2,2], using right continuity at 2-2 and left continuity at 22.

Answer 16 from the source-traced unit appendix.

C. Classifying discontinuities

Exercise 17

Classify the discontinuity of (x21)/(x1)(x^2-1)/(x-1) at 11.

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Removable.

Answer 17 from the source-traced unit appendix.
Exercise 18

Classify the discontinuity of x/x|x|/x at 00.

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Jump.

Answer 18 from the source-traced unit appendix.
Exercise 19

Classify the discontinuity of 1/(x2)21/(x-2)^2 at 22.

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Infinite.

Answer 19 from the source-traced unit appendix.
Exercise 20

Classify the discontinuity of sin(1/x)\sin(1/x) at 00.

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Oscillatory.

Answer 20 from the source-traced unit appendix.
Exercise 21

Find and classify every discontinuity of (x24)/(x2x2)(x^2-4)/(x^2-x-2).

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Hole at 22; vertical asymptote at 1-1.

Answer 21 from the source-traced unit appendix.
Exercise 22

Find and classify every discontinuity of (x29)/(x26x+9)(x^2-9)/(x^2-6x+9).

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Infinite discontinuity at 33 after one factor cancels.

Answer 22 from the source-traced unit appendix.
Exercise 23

Can changing one function value repair a jump? Explain.

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No; nearby one-sided behavior remains unequal.

Answer 23 from the source-traced unit appendix.
Exercise 24

Can changing one function value repair a vertical asymptote? Explain.

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No; nearby values remain unbounded.

Answer 24 from the source-traced unit appendix.

D. Repairing holes

Exercise 25

Find cc so f(2)=cf(2)=c makes (x24)/(x2)(x^2-4)/(x-2) continuous.

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44.

Answer 25 from the source-traced unit appendix.
Exercise 26

Find cc so f(3)=cf(3)=c makes (x29)/(x3)(x^2-9)/(x-3) continuous.

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66.

Answer 26 from the source-traced unit appendix.
Exercise 27

Find cc so f(1)=cf(1)=c makes (x31)/(x1)(x^3-1)/(x-1) continuous.

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33.

Answer 27 from the source-traced unit appendix.
Exercise 28

Find cc so f(4)=cf(4)=c makes (x2)/(x4)(\sqrt{x}-2)/(x-4) continuous.

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1/41/4.

Answer 28 from the source-traced unit appendix.
Exercise 29

Explain why no value at x=0x=0 makes x/x|x|/x continuous there.

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No value works because the one-sided limits are 1-1 and 11.

Answer 29 from the source-traced unit appendix.
Exercise 30

Explain why no value at x=2x=2 makes 1/(x2)1/(x-2) continuous there.

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No value works because the function is unbounded.

Answer 30 from the source-traced unit appendix.

E. Piecewise parameters

Exercise 31

Find kk so {kx+1,x<2,x+3,x2\begin{cases}kx+1,&x<2,\\x+3,&x\ge2\end{cases} is continuous at 22.

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k=2k=2.

Answer 31 from the source-traced unit appendix.
Exercise 32

Find aa so {2x+a,x<1,x2+3,x1\begin{cases}2x+a,&x<1,\\x^2+3,&x\ge1\end{cases} is continuous at 11.

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a=2a=2.

Answer 32 from the source-traced unit appendix.
Exercise 33

Find bb so {x2+b,x1,3x+1,x>1\begin{cases}x^2+b,&x\le-1,\\3x+1,&x>-1\end{cases} is continuous at 1-1.

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b=3b=-3.

Answer 33 from the source-traced unit appendix.
Exercise 34

Find mm so {mx4,x<3,2x+m,x3\begin{cases}mx-4,&x<3,\\2x+m,&x\ge3\end{cases} is continuous at 33.

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m=5m=5.

Answer 34 from the source-traced unit appendix.
Exercise 35

Determine whether any kk makes {kx+5,x<0,kx+2,x0\begin{cases}kx+5,&x<0,\\kx+2,&x\ge0\end{cases} continuous at 00.

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No value works.

Answer 35 from the source-traced unit appendix.
Exercise 36

Find a,ba,b so {ax+b,x<1,x2+1,1x<3,2x+a,x3\begin{cases}ax+b,&x<1,\\x^2+1,&1\le x<3,\\2x+a,&x\ge3\end{cases} is continuous at both joins.

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a=4,b=2a=4,b=-2.

Answer 36 from the source-traced unit appendix.
Exercise 37

Design a piecewise function with one parameter that becomes continuous when the parameter is 77.

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Answers vary.

Answer 37 from the source-traced unit appendix.
Exercise 38

Explain why setting left and right formulas equal is necessary but not always sufficient when the actual function value is defined by a third rule.

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The third rule must assign the common limiting value at the join.

Answer 38 from the source-traced unit appendix.

F. Intermediate Value Theorem and bisection

Exercise 39

Show that x32x2=0x^3-2x-2=0 has a root in (1,2)(1,2).

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Polynomial continuity and signs 3,2-3,2 at 1,21,2.

Answer 39 from the source-traced unit appendix.
Exercise 40

Show that x5+x2=0x^5+x-2=0 has a root in (0,2)(0,2).

Show answer

Polynomial continuity and signs 2,32-2,32 at 0,20,2.

Answer 40 from the source-traced unit appendix.
Exercise 41

Show that cosx=x\cos x=x has a solution in (0,1)(0,1).

Show answer

f(x)=cosxxf(x)=\cos x-x is continuous; f(0)=1f(0)=1, f(1)=cos11<0f(1)=\cos1-1<0.

Answer 41 from the source-traced unit appendix.
Exercise 42

Explain why a sign change is sufficient but not necessary for a root to exist.

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A function can touch zero and return without an endpoint sign change.

Answer 42 from the source-traced unit appendix.
Exercise 43

Give a continuous function with a root in (1,1)(-1,1) whose endpoint values have the same sign.

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Example: f(x)=x2f(x)=x^2 on [1,1][-1,1].

Answer 43 from the source-traced unit appendix.
Exercise 44

Explain why IVT cannot be applied to 1/x1/x on [1,1][-1,1], despite opposite endpoint signs.

Show answer

1/x1/x is not continuous on the interval because it is undefined at zero.

Answer 44 from the source-traced unit appendix.
Exercise 45

Use two bisection steps to narrow a root of x3+x1x^3+x-1 from (0,1)(0,1).

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After two steps, the root lies in (0.5,0.75)(0.5,0.75).

Answer 45 from the source-traced unit appendix.
Exercise 46

Use three bisection steps to narrow a root of x32x2x^3-2x-2 from (1,2)(1,2).

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After three steps, the root lies in (1.75,1.875)(1.75,1.875).

Answer 46 from the source-traced unit appendix.
Exercise 47

Does IVT prove uniqueness? Give an example supporting your answer.

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No. Example: x21x^2-1 has two roots on [2,2][-2,2].

Answer 47 from the source-traced unit appendix.
Exercise 48

State every hypothesis and conclusion in a complete IVT solution.

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State continuity on [a,b][a,b], an intermediate target between endpoint outputs, and the existence of c[a,b]c\in[a,b] with f(c)=Nf(c)=N.

Answer 48 from the source-traced unit appendix.

Answers begin in the referenced section.

After the explanation

Use the section idea

Reading lens

Do the limit, the function value, and the surrounding domain fit together at the point or across the interval?

Mental model

Continuity is a three-part agreement: the value exists, the two-sided limit exists, and those two quantities are equal.

Decision

At a point, test the three conditions in order; on an interval, check the domain and endpoints before invoking any continuity theorem.

Common trap

A sign change supports the Intermediate Value Theorem only when continuity holds on the entire closed interval, and it does not prove uniqueness.

Check yourself

You are ready to continue when you can classify a break, decide whether one value can repair it, and state every IVT hypothesis aloud.

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Vocab
Limit
Math glossaryLimit
limxaf(x)=L\lim_{x\to a}f(x)=L

The value a function approaches as its input approaches a target.

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Function
Math glossaryFunction
y=f(x)y=f(x)

A rule or relation assigning exactly one output to each allowed input.

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Continuity
Math glossaryContinuity
limxaf(x)=f(a)\lim_{x\to a}f(x)=f(a)

At a point, the function value exists and equals the limit there.

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Domain
Math glossaryDomain
domf\operatorname{dom}f

The set of permitted input values.

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Math glossary