Calculus I · Unit 3A · lesson

Accumulation Functions

Concept

Learning objectives

Interpret a variable-upper-limit integral as a new function and reason about its increase, decrease, and units.

Accumulation Functions

Explanation

An integral can define a new function

When the upper limit varies, A(x)=axf(t)dtA(x)=\int_a^x f(t)\,dt records how much signed accumulation has occurred by the time the input reaches xx. The dummy variable tt is used inside the integral so that xx can remain free to control the endpoint. As xx moves, the accumulated region grows, shrinks, or gains negative contribution depending on the sign of ff.

The graph of AA can often be predicted directly from the graph of ff. Where ff is positive, AA increases; where ff is negative, AA decreases; where f=0f=0, AA has a horizontal tangent. This makes accumulation functions a bridge between geometric area, net change, and derivative behavior, setting up the Fundamental Theorem rather than appearing as an isolated notation trick.

Fix a starting point aa and define

A(x)=axf(t)dt.A(x)=\int_a^x f(t)\,dt.

The variable tt is a dummy variable inside the integral; xx determines where accumulation stops.

If f>0f>0, moving xx to the right adds positive contributions and AA increases. If f<0f<0, AA decreases. The value A(x)A(x) is a total; the value f(x)f(x) is the local rate at which that total changes.

Worked example

Build an accumulation function directly

For f(t)=2tf(t)=2t and a=1a=1,

A(x)=1x2tdt=x21.A(x)=\int_1^x2t\,dt=x^2-1.

Thus A(1)=0A(1)=0, A(2)=3A(2)=3, and A(x)=2x=f(x)A'(x)=2x=f(x).

Interactive checku3a-accumulation-01

For A(x)=3xf(t)dtA(x)=\int_3^x f(t)\,dt, what is A(3)A(3)?

Your work stays on this device. No account or AI grader is used.

Show hint

The interval has zero width.

Attempt once to unlock the solution

Submit an answer first. The hint is available now.

Moving upper bound and accumulated area. Show A(x)=int a x f(t)dt changing as x moves.
Read this graph as text

Moving upper bound and accumulated area. As x moves, the shaded signed area updates and a point traces A(x). Show A(x)=int a x f(t)dt changing as x moves. Preserve sign when the integrand is below the axis.

Every relationship in moving upper bound and accumulated area uses written labels together with distinct line styles, markers, or fill patterns; color is never the only carrier of meaning.

Why it matters: Show A(x)=int a x f(t)dt changing as x moves.

Visual study

Moving upper bound and accumulated area. Show A(x)=int a x f(t)dt changing as x moves.

After the explanation

Use the section idea

Reading lens

Use the Fundamental Theorem as the bridge between accumulation functions, local rates, and endpoint evaluation.

Mental model

Differentiating a running total recovers its current integrand, while evaluating an accumulated total subtracts antiderivative endpoint values.

Decision

Separate FTC Part I, FTC Part II, net change, and variable-bound chain-rule tasks before manipulating notation.

Common trap

Forgetting a chain-rule factor at a variable bound, reversing endpoint subtraction, or adding +C to a definite value.

Check yourself

Can you state which part of the theorem applies and why its hypotheses and bounds fit?

Source & rights

Original instruction with traceable references.

BetterGrades-original; no direct adaptation declared in the verified handoff.

Reference textbooks remain rights-separated and are not published as application assets. Any direct adaptation requires separate identification and attribution.