Calculus I · Unit 3B · answer key

Unit 3B Practice Exam B Answer Key

Unit 3B Practice Exam B Answer Key

Finish an honest attempt first. Then compare one numbered response at a time, locate the first line where your reasoning diverged, and retry without the key open.

Answer 1

Problem 1

Intersections are x=1,2x=-1,2:

A=12(x+2x2)dx=92.A=\int_{-1}^{2}(x+2-x^2)dx=\frac92.
Answer 2

Problem 2

V=π01(1x2)2dx=8π15.V=\pi\int_0^1(1-x^2)^2dx=\frac{8\pi}{15}.
Answer 3

Problem 3

V=2π01x(1x2)dx=π2.V=2\pi\int_0^1x(1-x^2)dx=\frac{\pi}{2}.
Answer 4

Problem 4

The area of a semicircle with diameter dd is πd2/8\pi d^2/8, so

V=04π(2x)28dx=4π.V=\int_0^4\frac{\pi(2\sqrt{x})^2}{8}dx=4\pi.
Answer 5

Problem 5

S=2π01x1+12dx=π2.S=2\pi\int_0^1x\sqrt{1+1^2}dx=\pi\sqrt2.
Answer 6

Problem 6

m=01(1+x2)dx=43,xˉ=01x(1+x2)dxm=916.m=\int_0^1(1+x^2)dx=\frac43, \qquad \bar x=\frac{\int_0^1x(1+x^2)dx}{m}=\frac{9}{16}.
Answer 7

Problem 7

W=0.100.30200xdx=8 J.W=\int_{0.10}^{0.30}200x\,dx=8\text{ J}.
Answer 8

Problem 8

With yy measured from the bottom, slice volume is πdy\pi dy and lift distance is 3y3-y:

W=9800π02(3y)dy=39200π J.W=9800\pi\int_0^2(3-y)dy=39200\pi\text{ J}.
Answer 9

Problem 9

Let yy be depth below the surface. The width is 4(1y/3)4(1-y/3):

F=980003y4(1y3)dy=58800 N.F=9800\int_0^3 y\,4\left(1-\frac y3\right)dy=58800\text{ N}.
Answer 10

Problem 10

C(300)=2000+0300(15+0.02q)dq=7400.C(300)=2000+\int_0^{300}(15+0.02q)dq=7400.
Answer 11

Problem 11

013x2dx=1,E[X]=01x(3x2)dx=34.\int_0^1 3x^2dx=1, \qquad E[X]=\int_0^1x(3x^2)dx=\frac34.
Answer 12

Problem 12

Vertical strips are parallel to the yy-axis and create shells around the yy-axis; the same vertical strips are perpendicular to the xx-axis and create disks around the xx-axis. Both methods preserve the given xx-description without solving for an inverse function.

Answer 13

Problem 13

Units verify that the local contribution has the right physical dimension, while geometry determines radii, heights, widths, and distances. Ignoring either can yield a numerically evaluated integral that represents the wrong quantity.

After the explanation

Use the section idea

Reading lens

Mixed applications test modeling recognition: commit to a diagram and slice statement before looking for a familiar formula.

Mental model

A complete solution connects context, variable, bounds, slice contribution, integral, computation, units, interpretation, and a reasonableness check.

Decision

Classify the output and geometry first, solve from a blank start, then reveal one worked answer only to diagnose the earliest divergent decision.

Common trap

Reading a key before forming a setup or treating every wrong result as algebra when the real error was a radius, width, density, or bound.

Check yourself

Can you rebuild the setup without the answer open and defend every factor in a sentence?

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Original instruction with traceable references.

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