BetterGrades Precalculus · Unit 15 · Lesson

Arithmetic sequences

Derive and use a_n=a_1+(n-1)d and connect arithmetic sequences to sampled linear functions.

Textbook reading

The problem that opens the lesson

An auditorium has 1818 seats in row 11 and 44 more seats in each later row. How many seats are in row 3535?

Solution

Begin by identifying the mathematical object and the information that fixes it. Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor. The relevant conditions are not optional bookkeeping: Indexing from zero changes the intercept form but not the additive pattern. Following that structure gives 18+344=15418+34\cdot 4=154.

Why this works

Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Textbook reading

What this lesson is really about

An arithmetic sequence has a constant difference dd between consecutive terms.

Starting from a1,a_1, reaching term nn requires n1n-1 additions, giving an=a1+(n1)da_n=a_1+(n-1)d. The sequence is a linear function sampled at integer inputs.

The point is not merely to reproduce a formula. A learner should be able to identify the quantities or geometric objects involved, explain why the relationship has its stated form, and recognize when the same idea appears in a graph, table, diagram, or model.

Textbook reading

Why the relationship works

Differences, slope, and term index are different representations of the same additive structure.

Textbook reading

A reliable way to work

Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor.

Indexing from zero changes the intercept form but not the additive pattern.

After the symbolic work is complete, check the result. Depending on the lesson, this may mean substituting into an original equation, comparing coordinates, examining a graph, checking units, testing an interval, or confirming that every branch of a periodic solution has been included.

Textbook reading

What commonly goes wrong

A common error is using nd instead of (n1)d(n-1)d when a1a_1 is the first term.

The repair is to return to the definition and identify the first step where the invalid solution stops describing the original mathematical object. Later algebra cannot rescue a first step that changed the domain, orientation, branch, or meaning of the problem.

Textbook reading

Worked examples

Worked example 1

An auditorium has 1818 seats in row 11 and 44 more seats in each later row. How many seats are in row 3535?

Solution

Begin by identifying the mathematical object and the information that fixes it. Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor. The relevant conditions are not optional bookkeeping: Indexing from zero changes the intercept form but not the additive pattern. Following that structure gives 18+344=15418+34\cdot 4=154.

Why this works

Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Transfer example

Problem

Find dd from two indexed terms.

Worked development

Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. Starting from a1,a_1, reaching term nn requires n1n-1 additions, giving an=a1+(n1)da_n=a_1+(n-1)d. The sequence is a linear function sampled at integer inputs. Then apply the conditions explicitly: Indexing from zero changes the intercept form but not the additive pattern. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Arithmetic sequences model seating rows, straight-line depreciation, regular deposits, and evenly spaced measurements.

Reasoning example

Problem

Recover a1a_1 from a later term.

Worked development

Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. Starting from a1,a_1, reaching term nn requires n1n-1 additions, giving an=a1+(n1)da_n=a_1+(n-1)d. The sequence is a linear function sampled at integer inputs. Then apply the conditions explicitly: Indexing from zero changes the intercept form but not the additive pattern. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Arithmetic sequences model seating rows, straight-line depreciation, regular deposits, and evenly spaced measurements.

Worked example 4: quick check

Find the 50th50th term of 7,12,17,7,12,17,...

Solution

Begin by identifying the mathematical object and the information that fixes it. Identify two indexed terms, divide their value difference by index difference to find d, then recover a1a_1 or another anchor. The relevant conditions are not optional bookkeeping: Indexing from zero changes the intercept form but not the additive pattern. Following that structure gives 252252.

Why this works

Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Equal-spacing number-line terms. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.
Read this graph as text

Arithmetic sequences · Equal-spacing number-line terms. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1+(n-1)d and connect arithmetic sequences to sampled linear functions.

Anchor figure · Equal-spacing number-line terms

Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Differences, slope, and term index are different representations of the same additive structure. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Sampled linear graph. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for arithmetic sequences.
Read this graph as text

Arithmetic sequences · Sampled linear graph. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for arithmetic sequences. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1+(n-1)d and connect arithmetic sequences to sampled linear functions.

Mechanism figure · Sampled linear graph

Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for arithmetic sequences.

Index-offset n-1 derivation. Compare the valid path with the tempting shortcut. The figure shows why using nd instead of (n-1)d when a_1 is the first term leads to a false conclusion.
Read this graph as text

Arithmetic sequences · Index-offset n-1 derivation. Compare the valid path with the tempting shortcut. The figure shows why using nd instead of (n-1)d when a_1 is the first term leads to a false conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1+(n-1)d and connect arithmetic sequences to sampled linear functions.

Comparison and error figure · Index-offset n-1 derivation

Compare the valid path with the tempting shortcut. The figure shows why using nd instead of (n1)d(n-1)d when a1a_1 is the first term leads to a false conclusion.

Textbook reading

Application and interpretation

Arithmetic sequences model seating rows, straight-line depreciation, regular deposits, and evenly spaced measurements.

A contextual answer must include units, a meaningful domain, and the assumptions that make the model plausible. An exact mathematical relationship should not be diluted into a decimal unless a measurement or comparison requires it.

Check yourself

Find the 50th50th term of 7,12,17,7,12,17,...

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Practice

16 concrete questions

Practice 1 · retrieval · foundational01

Find the 50th50th term of 7,12,17,7,12,17,...

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Practice 2 · conceptual · foundational02

State the defining idea behind arithmetic sequences in one precise sentence.

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Practice 3 · verification · developing03

For arithmetic sequences, what condition or domain restriction must remain visible in the solution?

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Practice 4 · error analysis · developing04

For arithmetic sequences, describe the most likely incorrect first step and explain why it fails.

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Practice 5 · synthesis · transfer05

For arithmetic sequences, explain how this lesson's idea will be used later in the course.

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Practice 6 · procedural · foundational06

Solve this arithmetic sequences problem and state the final result: An auditorium has 1818 seats in row 11 and 44 more seats in each later row. How many seats are in row 3535?

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Practice 7 · procedural · developing07

In arithmetic sequences, for “Find dd from two indexed terms.”, identify the first valid mathematical step and the condition that must remain visible.

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Practice 8 · transfer · transfer08

For “Recover a1a_1 from a later term.”, identify the governing definition or relationship and what a complete conclusion must include.

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Practice 9 · verification · developing09

Verify “18+344=15418+34\cdot 4=154.” using the required condition for arithmetic sequences.

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Practice 10 · explanation · developing10

Explain why “18+344=15418+34\cdot 4=154.” follows from this lesson’s mathematical mechanism.

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Practice 11 · conceptual · developing11

What mathematical structure is shared by the opening problem and “Recover a1a_1 from a later term.”?

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Practice 12 · graphical · developing12

In “Equal-spacing number-line terms”, which mathematical objects or labels must be visible to support “18+344=15418+34\cdot 4=154.”?

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Practice 13 · graphical · transfer13

How should “Sampled linear graph” make the governing relationship in “Find dd from two indexed terms.” visible?

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Practice 14 · error analysis · transfer14

In “Index-offset n1n-1 derivation”, identify the first point where the misconception diverges from valid arithmetic sequences reasoning.

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Practice 15 · modeling · transfer15

In the application “Arithmetic sequences model seating rows, straight-line depreciation, regular deposits, and evenly spaced measurements.”, what quantities or geometric objects must be identified, and what condition makes the model valid?

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Practice 16 · exit check · transfer16

Answer “Find the 50th50th term of 7,12,17,7,12,17,...” and name the condition used to check the result.

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Textbook reading

Lesson summary

An arithmetic sequence has a constant difference dd between consecutive terms.

The central condition to remember is this: Indexing from zero changes the intercept form but not the additive pattern.

Connection forward

The next lesson replaces repeated addition with repeated multiplication.

The next lesson is Geometric sequences.

Source record

Original BetterGrades manuscript, rights-separated references.

  • Stitz & Zeager, Precalculus, Chapter 9
  • University of Washington Precalculus, discrete-model problems
  • AP Precalculus framework, sequence and model connections

No long source passage is reproduced.